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Determine the X Values That Cause the Function to Be f(x)=x2⋅∣2x+5∣f ( x ) = x ^ { 2 } \cdot | 2 x + 5 |

Question 79

Multiple Choice

Determine the x values that cause the function to be (a) zero, (b) undefined, (c) positive, and (d) negative.
- f(x) =x2⋅∣2x+5∣f ( x ) = x ^ { 2 } \cdot | 2 x + 5 |


A) (a) {−52,0}\left\{ - \frac { 5 } { 2 } , 0 \right\}
(b) ∅\varnothing
(c) (−52,0) ∪(0,∞) \left( - \frac { 5 } { 2 } , 0 \right) \cup ( 0 , \infty )
(d) (−∞,−52) \left( - \infty , - \frac { 5 } { 2 } \right)
B) (a) {−52,0}\left\{ - \frac { 5 } { 2 } , 0 \right\}
(b) ∅\varnothing (c) (−∞,∞) ( - \infty , \infty )
(d) ∅\varnothing
C) (a) {−52}\left\{ - \frac { 5 } { 2 } \right\}
(b) {0}\{ 0 \}
(c) (−52,0) ∪(0,∞) \left( - \frac { 5 } { 2 } , 0 \right) \cup ( 0 , \infty )
(d) (−∞,−52) \left( - \infty , - \frac { 5 } { 2 } \right)
D) (a) {−52,0}\left\{ - \frac { 5 } { 2 } , 0 \right\}
(b) ∅\varnothing (c) (−∞,−52) ∪(−52,0) ∪(0,∞) \left( - \infty , - \frac { 5 } { 2 } \right) \cup \left( - \frac { 5 } { 2 } , 0 \right) \cup ( 0 , \infty )
(d) ∅\varnothing

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