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Determine the X Values That Cause the Polynomial Function to Be

Question 176

Multiple Choice

Determine the x values that cause the polynomial function to be (a) zero, (b) positive, and (c) negative.
- f(x) =(x−7) (3x+5) (x+2) f ( x ) = ( x - 7 ) ( 3 x + 5 ) ( x + 2 )


A) (a) {−2,−53,7}\left\{ - 2 , - \frac { 5 } { 3 } , 7 \right\} , (b) (∞,−2) ∪(−53,7) ( \infty , - 2 ) \cup \left( - \frac { 5 } { 3 } , 7 \right) , (c) (−2,−53) ∪(7,∞) \left( - 2 , - \frac { 5 } { 3 } \right) \cup ( 7 , \infty )
B) (a) {−2,−53,7}\left\{ - 2 , - \frac { 5 } { 3 } , 7 \right\} (b) (−2,−53) ∪(7,∞) \left( - 2 , - \frac { 5 } { 3 } \right) \cup ( 7 , \infty ) , (c) (∞,−2) ∪(−53,7) ( \infty , - 2 ) \cup \left( - \frac { 5 } { 3 } , 7 \right)
C) (a) {−2,−5,7⟩\{ - 2 , - 5,7 \rangle , (b) (−2,−5) ∪(7,∞) ( - 2 , - 5 ) \cup ( 7 , \infty ) , (c) (∞,−2) ∪(−5,7) ( \infty , - 2 ) \cup ( - 5,7 )
D) (a) {−2,−53,7}\left\{ - 2 , - \frac { 5 } { 3 } , 7 \right\} (b) (−2,7) ( - 2,7 ) , (c) (∗,−2) ∪(7,∞) ( * , - 2 ) \cup ( 7 , \infty )

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