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Use a Cubic or Quartic Regression (As Specified) to Fit $y = - 0.01 x ^ { 4 } + 0.29 x ^ { 3 } - 0.06 x ^ { 2 } - 0.23 x + 3.23$

Question 157

Multiple Choice

Use a cubic or quartic regression (as specified) to fit a curve through the points given in the table. Round to the nearest
hundredth.
- $Use a cubic or quartic regression (as specified) to fit a curve through the points given in the table. Round to the nearest hundredth. - A) y = - 0.01 x ^ { 4 } + 0.29 x ^ { 3 } - 0.06 x ^ { 2 } - 0.23 x + 3.23 B) y \approx 0.01 x ^ { 4 } - 0.09 x ^ { 3 } - 0.08 x ^ { 2 } - 0.23 x + 3.23 C) y \approx - 0.01 x ^ { 4 } + 0.09 x ^ { 3 } - 0.08 x ^ { 2 } - 0.23 x + 3.23 D) y \approx - 0.01 x ^ { 4 } + 0.29 x ^ { 3 } - 0.16 x ^ { 2 } - 0.23 x + 2.26$

A) $y = - 0.01 x ^ { 4 } + 0.29 x ^ { 3 } - 0.06 x ^ { 2 } - 0.23 x + 3.23$
B) $y \approx 0.01 x ^ { 4 } - 0.09 x ^ { 3 } - 0.08 x ^ { 2 } - 0.23 x + 3.23$
C) $y \approx - 0.01 x ^ { 4 } + 0.09 x ^ { 3 } - 0.08 x ^ { 2 } - 0.23 x + 3.23$
D) $y \approx - 0.01 x ^ { 4 } + 0.29 x ^ { 3 } - 0.16 x ^ { 2 } - 0.23 x + 2.26$

Use a Cubic or Quartic Regression (As Specified) to Fit y=−0.01x4+0.29x3−0.06x2−0.23x+3.23y = - 0.01 x ^ { 4 } + 0.29 x ^ { 3 } - 0.06 x ^ { 2 } - 0.23 x + 3.23y=−0.01x4+0.29x3−0.06x2−0.23x+3.23

Multiple Choice

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Use a Cubic or Quartic Regression (As Specified) to Fit $y = - 0.01 x ^ { 4 } + 0.29 x ^ { 3 } - 0.06 x ^ { 2 } - 0.23 x + 3.23$

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