Solved

Solve the Problem 15 m15 \mathrm {~m} And Ranges from 10 To 20 m20 \mathrm {~m}

Question 354

Multiple Choice

Solve the problem.
-Tides go up and down in a 14.4-hour period. The average depth of a certain river is 15 m15 \mathrm {~m} and ranges from 10 to 20 m20 \mathrm {~m} . The variation can be approximated by a sine curve. Write an equation that gives the approximate variation yy , if xx is the number of hours after midnight if high tide occurs at 6:006 : 00 am.


A) y=15sin⁡(πx7.2−6π7.2) y = 15 \sin \left( \frac { \pi x } { 7.2 } - \frac { 6 \pi } { 7.2 } \right)
B) y=5sin⁡(πx7.2−6π7.2) y = 5 \sin \left( \frac { \pi x } { 7.2 } - \frac { 6 \pi } { 7.2 } \right)
C) y=15sin⁡(πx7.2−6π) y = 15 \sin \left( \frac { \pi x } { 7.2 } - 6 \pi \right)
D) y=5sin⁡(πx7.2−2.4π7.2) y = 5 \sin \left( \frac { \pi x } { 7.2 } - \frac { 2.4 \pi } { 7.2 } \right)

Correct Answer:

verifed

Verified

Unlock this answer now
Get Access to more Verified Answers free of charge

Related Questions