Identify the Maximum and Minimum Values of the Function in the Interval

Identify the maximum and minimum values of the function in the interval $[-2 \pi, 2 \pi]$ . Use your understanding of transformations, not your graphing calculator.
- $$y = \frac { 1 } { 2 } \sin 2 x$$

A) Maximum value $= \frac { 1 } { 2 } ;$ minimum value $= - \frac { 1 } { 2 }$
B) Maximum value $= \frac { 1 } { 2 } ;$ minimum value $= 0$
C) Maximum value $= \frac { 1 } { 4 } ;$ minimum value $= - \frac { 1 } { 4 }$
D) Maximum value $= 2$ ; minimum value $= - 2$

Correct Answer:

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