Find the Partial Fraction Decomposition $$\frac { 3 } { x ^ { 2 } + 4 x + 3 } = \frac { A } { x + 3 } + \frac { B } { x + 1 }$$

Find the partial fraction decomposition.
- $$\frac { 3 } { x ^ { 2 } + 4 x + 3 } = \frac { A } { x + 3 } + \frac { B } { x + 1 }$$

A) $A = - \frac { 3 } { 2 } , B = - \frac { 3 } { 2 }$
B) $A = \frac { 3 } { 2 } , B = \frac { 3 } { 2 }$
C) $\mathrm { A } = \frac { 3 } { 2 } , \mathrm {~B} = - \frac { 3 } { 2 }$
D) $\mathrm { A } = - \frac { 3 } { 2 } , \mathrm {~B} = \frac { 3 } { 2 }$

Correct Answer:

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