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Determine the Eccentricity, the Type of Conic, and the Directrix r=36+8cos⁡θr = \frac { 3 } { 6 + 8 \cos \theta }

Question 9

Multiple Choice

Determine the eccentricity, the type of conic, and the directrix.
- r=36+8cos⁡θr = \frac { 3 } { 6 + 8 \cos \theta }


A) Eccentricity =43;= \frac { 4 } { 3 } ; parabola; directrix x=−94x = - \frac { 9 } { 4 }
B) Eccentricity =83;= \frac { 8 } { 3 } ; ellipse; directrix y=−4y = - 4
C) Eccentricity =34= \frac { 3 } { 4 } ; ellipse; directrix x=−4x = - 4
D) Eccentricity =43;= \frac { 4 } { 3 } ; hyperbola; directrix x=38x = \frac { 3 } { 8 }

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