Find the Sum $\sum _ { k = 1 } ^ { n } \left( k ^ { 2 } + 9 k + 20 \right)$

Find the sum.
- $\sum _ { k = 1 } ^ { n } \left( k ^ { 2 } + 9 k + 20 \right)$

A) $\frac { n ( n + 1 ) ( 2 n + 1 ) } { 6 } + \frac { 9 n ( n + 1 ) } { 2 } + 20 n$
B) $\frac { n ( n + 1 ) ( 2 n + 1 ) } { 6 } + \frac { 9 n ( n + 1 ) } { 2 }$
C) $\frac { 9 n ( n + 1 ) } { 2 } + 20 n$
D) $\frac { n ( n + 1 ) ( 2 n + 1 ) } { 6 } + 20 n$

Correct Answer:

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