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Find the Sum ∑k=1n(k2+5)\sum _ { k = 1 } ^ { n } \left( k ^ { 2 } + 5 \right)

Question 87

Multiple Choice

Find the sum.
- ∑k=1n(k2+5) \sum _ { k = 1 } ^ { n } \left( k ^ { 2 } + 5 \right)


A) n(n+1) (2n+1) +30n6\frac { n ( n + 1 ) ( 2 n + 1 ) + 30 n } { 6 }
B) n(n+1) (2n+1) +6n6\frac { n ( n + 1 ) ( 2 n + 1 ) + 6 n } { 6 }
C) n(n+1) (2n+1) +306\frac { n ( n + 1 ) ( 2 n + 1 ) + 30 } { 6 }
D) n(n+1) (2n+1) 6\frac { n ( n + 1 ) ( 2 n + 1 ) } { 6 }

Correct Answer:

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