Tunneling: an Electron with Kinetic Energy 2

Tunneling: An electron with kinetic energy 2.80 eV encounters a potential barrier of height 4.70 eV. If the barrier width is 0.40 nm, what is the probability that the electron will tunnel through the barrier? (1 eV = 1.60 × 10^-19 J, m_el = 9.11 × 10^-31 kg, ħ = 1.055 × 10^-34 J ∙ s, h = 6.626 × 10^-34 J ∙ s)

A) 3.5 × 10^-3
B) 7.3 × 10^-3
C) 1.4 × 10^-2
D) 2.9 × 10^-3
E) 3.5 × 10^-2

Correct Answer:

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