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-Supply Missing Statements and Missing Reasons for the Following Proof

Question 11

Essay

-Supply missing statements and missing reasons for the following proof.
Given: ; bisects and Prove: is an isosceles triangle
S1. ; bisects R1.
S2. R2. If a ray bisects one of a , it divides the opposite
side into segments whose lengths are proportional to
the lengths of the two sides that form the bisected -Supply missing statements and missing reasons for the following proof. Given: ; bisects and Prove: is an isosceles triangle S1. ; bisects R1. S2. R2. If a ray bisects one of a , it divides the opposite side into segments whose lengths are proportional to the lengths of the two sides that form the bisected . S3. R3. Given S4. R4. S5. , so R5. S6. R6. S7. R7. .
S3. R3. Given
S4. -Supply missing statements and missing reasons for the following proof. Given: ; bisects and Prove: is an isosceles triangle S1. ; bisects R1. S2. R2. If a ray bisects one of a , it divides the opposite side into segments whose lengths are proportional to the lengths of the two sides that form the bisected . S3. R3. Given S4. R4. S5. , so R5. S6. R6. S7. R7. R4.
S5. -Supply missing statements and missing reasons for the following proof. Given: ; bisects and Prove: is an isosceles triangle S1. ; bisects R1. S2. R2. If a ray bisects one of a , it divides the opposite side into segments whose lengths are proportional to the lengths of the two sides that form the bisected . S3. R3. Given S4. R4. S5. , so R5. S6. R6. S7. R7. , so -Supply missing statements and missing reasons for the following proof. Given: ; bisects and Prove: is an isosceles triangle S1. ; bisects R1. S2. R2. If a ray bisects one of a , it divides the opposite side into segments whose lengths are proportional to the lengths of the two sides that form the bisected . S3. R3. Given S4. R4. S5. , so R5. S6. R6. S7. R7. R5.
S6. -Supply missing statements and missing reasons for the following proof. Given: ; bisects and Prove: is an isosceles triangle S1. ; bisects R1. S2. R2. If a ray bisects one of a , it divides the opposite side into segments whose lengths are proportional to the lengths of the two sides that form the bisected . S3. R3. Given S4. R4. S5. , so R5. S6. R6. S7. R7. R6.
S7. R7.