Solve the Equation in the Real Number System $$2 x ^ { 3 } - x ^ { 2 } - 6 x + 3 = 0$$

Solve the equation in the real number system.
- $$2 x ^ { 3 } - x ^ { 2 } - 6 x + 3 = 0$$

A) $\{ 2 , \sqrt { 3 } , - \sqrt { 3 } \}$
B) $\left\{ - \frac { 1 } { 2 } , \sqrt { 3 } , - \sqrt { 3 } \right\}$
C) $\left\{ \frac { 1 } { 2 } , \sqrt { 3 } , - \sqrt { 3 } \right\}$
D) $\{ - 2 , \sqrt { 3 } , - \sqrt { 3 } \}$

Correct Answer:

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