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Find an Equation for the Ellipse Described (x+2)249+(y−3)240=1\frac { ( x + 2 ) ^ { 2 } } { 49 } + \frac { ( y - 3 ) ^ { 2 } } { 40 } = 1

Question 22

Multiple Choice

Find an equation for the ellipse described. Graph the equation.
-Foci at (1, 3) and (-5, 3) ; vertex at (-9, 3)  Find an equation for the ellipse described. Graph the equation. -Foci at (1, 3)  and (-5, 3) ; vertex at (-9, 3)    A)   \frac { ( x + 2 )  ^ { 2 } } { 49 } + \frac { ( y - 3 )  ^ { 2 } } { 40 } = 1    B)   \frac { ( x - 3 )  ^ { 2 } } { 49 } + \frac { ( y + 2 )  ^ { 2 } } { 40 } = 1    C)   \frac { ( x + 2 )  ^ { 2 } } { 40 } + \frac { ( y - 3 )  ^ { 2 } } { 49 } = 1    D)   \frac { ( x - 3 )  ^ { 2 } } { 40 } + \frac { ( y + 2 )  ^ { 2 } } { 49 } = 1


A) (x+2) 249+(y−3) 240=1\frac { ( x + 2 ) ^ { 2 } } { 49 } + \frac { ( y - 3 ) ^ { 2 } } { 40 } = 1
 Find an equation for the ellipse described. Graph the equation. -Foci at (1, 3)  and (-5, 3) ; vertex at (-9, 3)    A)   \frac { ( x + 2 )  ^ { 2 } } { 49 } + \frac { ( y - 3 )  ^ { 2 } } { 40 } = 1    B)   \frac { ( x - 3 )  ^ { 2 } } { 49 } + \frac { ( y + 2 )  ^ { 2 } } { 40 } = 1    C)   \frac { ( x + 2 )  ^ { 2 } } { 40 } + \frac { ( y - 3 )  ^ { 2 } } { 49 } = 1    D)   \frac { ( x - 3 )  ^ { 2 } } { 40 } + \frac { ( y + 2 )  ^ { 2 } } { 49 } = 1
B) (x−3) 249+(y+2) 240=1\frac { ( x - 3 ) ^ { 2 } } { 49 } + \frac { ( y + 2 ) ^ { 2 } } { 40 } = 1
 Find an equation for the ellipse described. Graph the equation. -Foci at (1, 3)  and (-5, 3) ; vertex at (-9, 3)    A)   \frac { ( x + 2 )  ^ { 2 } } { 49 } + \frac { ( y - 3 )  ^ { 2 } } { 40 } = 1    B)   \frac { ( x - 3 )  ^ { 2 } } { 49 } + \frac { ( y + 2 )  ^ { 2 } } { 40 } = 1    C)   \frac { ( x + 2 )  ^ { 2 } } { 40 } + \frac { ( y - 3 )  ^ { 2 } } { 49 } = 1    D)   \frac { ( x - 3 )  ^ { 2 } } { 40 } + \frac { ( y + 2 )  ^ { 2 } } { 49 } = 1
C) (x+2) 240+(y−3) 249=1\frac { ( x + 2 ) ^ { 2 } } { 40 } + \frac { ( y - 3 ) ^ { 2 } } { 49 } = 1
 Find an equation for the ellipse described. Graph the equation. -Foci at (1, 3)  and (-5, 3) ; vertex at (-9, 3)    A)   \frac { ( x + 2 )  ^ { 2 } } { 49 } + \frac { ( y - 3 )  ^ { 2 } } { 40 } = 1    B)   \frac { ( x - 3 )  ^ { 2 } } { 49 } + \frac { ( y + 2 )  ^ { 2 } } { 40 } = 1    C)   \frac { ( x + 2 )  ^ { 2 } } { 40 } + \frac { ( y - 3 )  ^ { 2 } } { 49 } = 1    D)   \frac { ( x - 3 )  ^ { 2 } } { 40 } + \frac { ( y + 2 )  ^ { 2 } } { 49 } = 1
D) (x−3) 240+(y+2) 249=1\frac { ( x - 3 ) ^ { 2 } } { 40 } + \frac { ( y + 2 ) ^ { 2 } } { 49 } = 1
 Find an equation for the ellipse described. Graph the equation. -Foci at (1, 3)  and (-5, 3) ; vertex at (-9, 3)    A)   \frac { ( x + 2 )  ^ { 2 } } { 49 } + \frac { ( y - 3 )  ^ { 2 } } { 40 } = 1    B)   \frac { ( x - 3 )  ^ { 2 } } { 49 } + \frac { ( y + 2 )  ^ { 2 } } { 40 } = 1    C)   \frac { ( x + 2 )  ^ { 2 } } { 40 } + \frac { ( y - 3 )  ^ { 2 } } { 49 } = 1    D)   \frac { ( x - 3 )  ^ { 2 } } { 40 } + \frac { ( y + 2 )  ^ { 2 } } { 49 } = 1

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