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A Geometric Sequence Is Given {4(12)n−1}\left\{ 4 \left( \frac { 1 } { 2 } \right) ^ { n - 1 } \right\}

Question 92

Multiple Choice

A geometric sequence is given. Find the common ratio and write out the first four terms.
- {4(12) n−1}\left\{ 4 \left( \frac { 1 } { 2 } \right) ^ { n - 1 } \right\}


A) an=4⋅(2) n−1a _ { n } = 4 \cdot ( 2 ) ^ { n - 1 }
r=2;4,8,16,32,…r = 2 ; 4,8,16,32 , \ldots
B) an=12(4) n−1a _ { n } = \frac { 1 } { 2 } ( 4 ) ^ { n - 1 }
r=12;4,8,16,32,…\mathrm { r } = \frac { 1 } { 2 } ; 4,8,16,32 , \ldots
C) an=4(12) n−1\mathrm { a } _ { \mathrm { n } } = 4 \left( \frac { 1 } { 2 } \right) ^ { \mathrm { n } - 1 }
r=12;4,2,1,12,…\mathrm { r } = \frac { 1 } { 2 } ; 4,2,1 , \frac { 1 } { 2 } , \ldots
D) an=4(14) n−1\mathrm { a } _ { \mathrm { n } } = 4 \left( \frac { 1 } { 4 } \right) ^ { \mathrm { n } - 1 }
r=14;4,1,14,116,…r = \frac { 1 } { 4 } ; 4,1 , \frac { 1 } { 4 } , \frac { 1 } { 16 } , \ldots

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