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The Binomial Theorem States That for Any Real Numbers a and B

Question 6

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The binomial theorem states that for any real numbers a and b, (a+b)n=∑k=0n(nk)an−kbk for any integer n≥0( a + b ) ^ { n } = \sum _ { k = 0 } ^ { n } \left( \begin{array} { l } n \\k\end{array} \right) a ^ { n - k } b ^ { k } \quad \text { for any integer } n \geq 0
Use this theorem to show that for any integer n≥0,∑k=0n(−1)k(nk)3n−k2k=1n \geq 0 , \sum _ { k = 0 } ^ { n } ( - 1 ) ^ { k } \left( \begin{array} { l } n \\k\end{array} \right) 3 ^ { n - k } 2 ^ { k } = 1

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Proof: According to the binomial theorem...

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