Given the Equation Below, Determine Two Solutions Such That $0 ^ { \circ } \leq \theta < 360 ^ { \circ }$

Given the equation below, determine two solutions such that $0 ^ { \circ } \leq \theta < 360 ^ { \circ }$ .
$$\sin \theta = - \frac { \sqrt { 3 } } { 2 }$$

A) $\theta = 120 ^ { \circ } , 240 ^ { \circ }$
B) $\theta = 240 ^ { \circ } , 300 ^ { \circ }$
C) $\theta = 150 ^ { \circ } , 210 ^ { \circ }$
D) $\theta = 135 ^ { \circ } , 225 ^ { \circ }$
E) $\theta = 225 ^ { \circ } , 315 ^ { \circ }$

Correct Answer:

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