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Find a Solution for the Equation $\sin \left( 2 \beta + 5 ^ { \circ } \right) = \cos \left( 3 \beta - 25 ^ { \circ } \right)$

Question 90

Multiple Choice

Find a solution for the equation. Assume that all angles are acute angles.
- $\sin \left( 2 \beta + 5 ^ { \circ } \right) = \cos \left( 3 \beta - 25 ^ { \circ } \right)$

A) $23 ^ { \circ }$
B) $21.5 ^ { \circ }$
C) $22 ^ { \circ }$
D) $24 ^ { \circ }$

Find a Solution for the Equation sin⁡(2β+5∘)=cos⁡(3β−25∘)\sin \left( 2 \beta + 5 ^ { \circ } \right) = \cos \left( 3 \beta - 25 ^ { \circ } \right)sin(2β+5∘)=cos(3β−25∘)

Multiple Choice

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Find a Solution for the Equation $\sin \left( 2 \beta + 5 ^ { \circ } \right) = \cos \left( 3 \beta - 25 ^ { \circ } \right)$

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