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Solve the Problem dd From a Long Wall dd Is Given By d=4tan⁡2πt\mathrm { d } = 4 \tan 2 \pi \mathrm { t }

Question 21

Multiple Choice

Solve the problem.
-A rotating beacon is located a distance dd from a long wall. The distance dd is given by d=4tan⁡2πt\mathrm { d } = 4 \tan 2 \pi \mathrm { t } ,
where tt is the time measured in seconds since the beacon started rotating. Solve the equation for tt .


A) t=12πarctan⁡d4\mathrm { t } = \frac { 1 } { 2 \pi } \arctan \frac { \mathrm { d } } { 4 }
B) t=2πtan⁡d4t = 2 \pi \tan \frac { d } { 4 }
C) t=12πtan⁡d4\mathrm { t } = \frac { 1 } { 2 \pi } \tan \frac { \mathrm { d } } { 4 }
D) t=2πarctan⁡d4\mathrm { t } = 2 \pi \arctan \frac { \mathrm { d } } { 4 }

Correct Answer:

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