The Tonga Trench in the Pacific Ocean Is 36,000 Feet $1.04 \mathrm {~g} / \mathrm { cm } ^ { 3 }$

The Tonga Trench in the Pacific Ocean is 36,000 feet deep. Assuming that sea water has an average density of $1.04 \mathrm {~g} / \mathrm { cm } ^ { 3 }$ calculate the absolute (total) pressure at the bottom of the trench in atmospheres. $\left( 1.00 \mathrm { in } = 2.54 \mathrm {~cm} , 1.00 \mathrm {~atm} = 1.01 \times 10 ^ { 5 } \mathrm {~Pa} \right)$

A) $1.1 \times 10 ^ { 6 } \text { atm }$
B) $1.1 \times 10 ^ { 8 } \mathrm {~atm}$
C) $1.1 \times 10 ^ { 3 } \text { atm }$
D) 2.1 atm
E) $1.1 \times 10 ^ { 5 } \mathrm {~atm}$

Correct Answer:

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