A 20-Kg Ice Cube At At 0.0 $0.0 ^ { \circ } \mathrm { C }$

A .20-kg ice cube at $0.0 ^ { \circ } \mathrm { C }$ has sufficient heat added to it to cause total melting, and the resulting water is heated to $70.0 ^ { \circ } \mathrm { C }$ How much heat is added? For water $L _ { F } = 334,000 \mathrm {~J} / \mathrm { kg } , L \mathrm {~V} = 2.256 \times 10 ^ { 6 }$ $\mathrm { J } / \mathrm { kq } _ { \text {, the } c } = 4.186 \times 10 ^ { 3 } \mathrm {~J} / \mathrm { kq } \cdot \mathrm { C } \text {. }$

A) 81 kJ
B) 59 kJ
C) 130 kJ
D) 14,000 kJ

Correct Answer:

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