$\mathrm { A } + 5.0 - \mu \mathrm { C }$

$\mathrm { A } + 5.0 - \mu \mathrm { C }$ point charge is placed at the $0 \mathrm {~cm}$ mark of a meter stick and a $- 4.0 - \mu \mathrm { C }$ charge is placed at the $50 \mathrm {~cm}$ mark. What is the net electric field at the $30 \mathrm {~cm}$ mark? $\left( k = 1 / 4 \pi \varepsilon _ { 0 } = 8.99 \times 10 ^ { 9 } \mathrm {~N} \right.$ . $m ^ { 2 } / C ^ { 2 }$ )

A) $1.4 \times 10 ^ { 6 } \mathrm {~N} / \mathrm { C }$
B) $5.0 \times 10 ^ { 5 } \mathrm {~N} / \mathrm { C }$
C) $4.0 \times 10 ^ { 5 } \mathrm {~N} / \mathrm { C }$
D) $9.0 \times 10 ^ { 5 } \mathrm {~N} / \mathrm { C }$

Correct Answer:

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