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An Electron Is Projected with an Initial Velocity v0=8.4×107 m/sv _ { 0 } = 8.4 \times 10 ^ { 7 } \mathrm {~m} / \mathrm { s }

Question 92

Multiple Choice

An electron is projected with an initial velocity v0=8.4×107 m/sv _ { 0 } = 8.4 \times 10 ^ { 7 } \mathrm {~m} / \mathrm { s } along the yy -axis, which is the centerline between a pair of charged plates, as shown in the figure. The plates are 1.0 m1.0 \mathrm {~m} long and are separated by 0.10 m0.10 \mathrm {~m} . A uniform electric field of magnitude EE in the +x+ x -direction is present between the plates. If the magnitude of the acceleration of the electron is measured to be 8.9×1015 m/s28.9 \times 10 ^ { 15 } \mathrm {~m} / \mathrm { s } ^ { 2 } , what is the magnitude of the electric field between the plates? (e=1.6×10−19C\left( e = 1.6 \times 10 ^ { - 19 } \mathrm { C } \right. , melectron =9.11×10−31 kgm _ { \text {electron } } = 9.11 \times 10 - 31 \mathrm {~kg} )
 An electron is projected with an initial velocity  v _ { 0 } = 8.4 \times 10 ^ { 7 } \mathrm {~m} / \mathrm { s }  along the  y -axis, which is the centerline between a pair of charged plates, as shown in the figure. The plates are  1.0 \mathrm {~m}  long and are separated by  0.10 \mathrm {~m} . A uniform electric field of magnitude  E  in the  + x -direction is present between the plates. If the magnitude of the acceleration of the electron is measured to be  8.9 \times 10 ^ { 15 } \mathrm {~m} / \mathrm { s } ^ { 2 } , what is the magnitude of the electric field between the plates?  \left( e = 1.6 \times 10 ^ { - 19 } \mathrm { C } \right. ,  m _ { \text {electron } } = 9.11 \times 10 - 31 \mathrm {~kg}  )    A)   35,000 \mathrm {~N} / \mathrm { C }  B)   29,000 \mathrm {~N} / \mathrm { C }  C)   40,000 \mathrm {~N} / \mathrm { C }  D)   51,000 \mathrm {~N} / \mathrm { C }  E)   45,000 \mathrm {~N} / \mathrm { C }


A) 35,000 N/C35,000 \mathrm {~N} / \mathrm { C }
B) 29,000 N/C29,000 \mathrm {~N} / \mathrm { C }
C) 40,000 N/C40,000 \mathrm {~N} / \mathrm { C }
D) 51,000 N/C51,000 \mathrm {~N} / \mathrm { C }
E) 45,000 N/C45,000 \mathrm {~N} / \mathrm { C }

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