An Ideal Solenoid with 400 Turns Has a Radius Of 0.040

An ideal solenoid with 400 turns has a radius of $0.040 \mathrm {~m}$ and is $40 \mathrm {~cm}$ long. If this solenoid carries a current of $12 \mathrm {~A}$ , what is the magnitude of the magnetic field at the center of the solenoid? $\left( \mu _ { 0 } = 4 \pi \right.$ $\times 10 ^ { - 7 } \mathrm {~T} \cdot \mathrm { m } / \mathrm { A }$ )

A) $16 \mathrm { mT }$
B) $9.0 \mathrm { mT }$
C) $6.0 \mathrm { mT }$
D) $4.9 \mathrm { mT }$
E) $15 \mathrm { mT }$

Correct Answer:

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