A Proton Is Projected with a Velocity of 7 $1.60 \times 10 ^ { - 19 } \mathrm { C }$

A proton is projected with a velocity of 7.0 km/s into a magnetic field of 0.60 T perpendicular to the motion of the proton. What is the magnitude of the magnetic force that acts on the proton? (e = $1.60 \times 10 ^ { - 19 } \mathrm { C }$ )

A) $13 \times 10 ^ { - 16 } \mathrm {~N}$
B) $6.7 \times 10 ^ { - 16 } \mathrm {~N}$
C) $0 \mathrm {~N}$
D) $3.4 \times 10 ^ { - 16 } \mathrm {~N}$
E) $4.2 \times 10 ^ { - 16 } \mathrm {~N}$

Correct Answer:

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