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A Geophysicist Measures the Magnetic Force on a Proton That 1.996 km/s1.996 \mathrm {~km} / \mathrm { s }

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A geophysicist measures the magnetic force on a proton that is moving vertically downward at a point 1.996 km/s1.996 \mathrm {~km} / \mathrm { s } at the earth's equator. At that Iocation, the earth's magnetic magnetic field is horizontal and has a strength of 0.40×10−4 T0.40 \times 10 ^ { - 4 } \mathrm {~T} . What are the magnitude and direction of the force she will measure? (e=1.60×10−19C)\left( e = 1.60 \times 10 ^ { - 19 } \mathrm { C } \right)

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