A Diatomic Molecule Has $2.6 \times 10 ^ { - 5 } \mathrm { eV }$

A diatomic molecule has $2.6 \times 10 ^ { - 5 } \mathrm { eV }$ of rotational energy in the $L = 2$ quantum state. What is its rotational energy in the $L = 1$ quantum state? $\left( 1 \mathrm { eV } = 1.60 \times 10 ^ { - 19 } \mathrm {~J} , h = 6.626 \times 10 ^ { - 34 } \mathrm {~J} \cdot \mathrm { s } \right)$

A) $3.4 \times 10 ^ { - 6 } \mathrm { eV }$
B) $5.3 \times 10 ^ { - 6 } \mathrm { eV }$
C) $8.7 \times 10 ^ { - 6 } \mathrm { eV }$
D) $7.8 \times 10 ^ { - 6 } \mathrm { eV }$

Correct Answer:

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