An Excited ${ } _ { 92 } ^ { 236 } \mathrm { U } ^ { * }$

An excited ${ } _ { 92 } ^ { 236 } \mathrm { U } ^ { * }$ nucleus undergoes fission into two fragments as follows:
$${ } _ { 92 } ^ { 236 } \mathrm { U } ^ { * } \rightarrow { } _ { 56 } ^ { 144 } \mathrm { Ba } + { } _ { 36 } ^ { 92 } \mathrm { Kr }$$
If, at the instant of fission, the $\mathrm { Ba }$ and $\mathrm { Kr }$ fragments are spherical and just barely in contact, what is the electrostatic potential energy of these two fragments? ( $1 \mathrm { eV } = 1.60 \times 10 ^ { - 19 } \mathrm {~J} , e = 1.60 \times 10 ^ { - 19 } \mathrm { C }$ , $1 / 4 \pi \varepsilon _ { 0 } = 8.99 \times 10 ^ { 9 } \mathrm {~N} \cdot \mathrm { m } ^ { 2 } / \mathrm { C } ^ { 2 }$ )

A) $270 \mathrm { MeV }$
B) $240 \mathrm { MeV }$
C) $260 \mathrm { MeV }$
D) $230 \mathrm { MeV }$
E) $250 \mathrm { MeV }$

Correct Answer:

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