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Factor Completely 125w3+127125 w ^ { 3 } + \frac { 1 } { 27 }

Question 141

Multiple Choice

Factor completely. 125w3+127125 w ^ { 3 } + \frac { 1 } { 27 }


A) (5w+13) (25w2−53w+19) \left( 5 w + \frac { 1 } { 3 } \right) \left( 25 w ^ { 2 } - \frac { 5 } { 3 } w + \frac { 1 } { 9 } \right)
B) (5w−13) (25w2+53w+19) \left( 5 w - \frac { 1 } { 3 } \right) \left( 25 w ^ { 2 } + \frac { 5 } { 3 } w + \frac { 1 } { 9 } \right)
C) (5w+13) (25w2−103w+19) \left( 5 w + \frac { 1 } { 3 } \right) \left( 25 w ^ { 2 } - \frac { 10 } { 3 } w + \frac { 1 } { 9 } \right)
D) Prime

Correct Answer:

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