Solve For $d _ { 1 }$ $$\frac { 1 } { f } = \frac { 1 } { d _ { 1 } } + \frac { 1 } { d _ { 2 } }$$

Solve for $d _ { 1 }$ .
$$\frac { 1 } { f } = \frac { 1 } { d _ { 1 } } + \frac { 1 } { d _ { 2 } }$$

A) $d _ { 1 } = \frac { d _ { 2 } f - d _ { 1 } f } { d _ { 2 } }$
B) $d _ { 1 } = \frac { 1 } { f - d _ { 2 } }$
C) $d _ { 1 } = f - d _ { 2 }$
D) $d _ { 1 } = \frac { f d _ { 2 } } { d _ { 2 } - f }$

Correct Answer:

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