Solve the Equation by Using the Quadratic Formula $6 y + 3 = - 4 y ^ { 2 }$

Solve the equation by using the quadratic formula. $6 y + 3 = - 4 y ^ { 2 }$

A) $\left\{ - \frac { 1 } { 4 } + \frac { \sqrt { 105 } } { 12 } , - \frac { 1 } { 4 } - \frac { \sqrt { 105 } } { 12 } \right\}$
B) $\left\{ - \frac { 9 } { 2 } , \frac { 1 } { 3 } \right\}$
C) $\left\{ - \frac { 3 } { 4 } + \frac { i \sqrt { 3 } } { 4 } , - \frac { 3 } { 4 } - \frac { i \sqrt { 3 } } { 4 } \right\}$
D) $\{ 2 + \sqrt { 3 } , 2 - \sqrt { 3 } \}$

Correct Answer:

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