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Solve the Inequality $( 3 x - 1 ) ( x + 6 ) \leq 0$

Question 225

Multiple Choice

Solve the inequality. Graph the solution set and write the solution set in interval notation.
- $( 3 x - 1 ) ( x + 6 ) \leq 0$
$Solve the inequality. Graph the solution set and write the solution set in interval notation. - ( 3 x - 1 ) ( x + 6 ) \leq 0 A) \left[ - \infty , \frac { 1 } { 3 } \right] B) [ - 6 , \infty ) C) \left[ - 6 , \frac { 1 } { 3 } \right] D) ( - \infty , - 6 ] \cup \left[ \frac { 1 } { 3 } , \infty \right]$

A) $\left[ - \infty , \frac { 1 } { 3 } \right]$
$Solve the inequality. Graph the solution set and write the solution set in interval notation. - ( 3 x - 1 ) ( x + 6 ) \leq 0 A) \left[ - \infty , \frac { 1 } { 3 } \right] B) [ - 6 , \infty ) C) \left[ - 6 , \frac { 1 } { 3 } \right] D) ( - \infty , - 6 ] \cup \left[ \frac { 1 } { 3 } , \infty \right]$
B) $[ - 6 , \infty )$
$Solve the inequality. Graph the solution set and write the solution set in interval notation. - ( 3 x - 1 ) ( x + 6 ) \leq 0 A) \left[ - \infty , \frac { 1 } { 3 } \right] B) [ - 6 , \infty ) C) \left[ - 6 , \frac { 1 } { 3 } \right] D) ( - \infty , - 6 ] \cup \left[ \frac { 1 } { 3 } , \infty \right]$
C) $\left[ - 6 , \frac { 1 } { 3 } \right]$
$Solve the inequality. Graph the solution set and write the solution set in interval notation. - ( 3 x - 1 ) ( x + 6 ) \leq 0 A) \left[ - \infty , \frac { 1 } { 3 } \right] B) [ - 6 , \infty ) C) \left[ - 6 , \frac { 1 } { 3 } \right] D) ( - \infty , - 6 ] \cup \left[ \frac { 1 } { 3 } , \infty \right]$
D) $( - \infty , - 6 ] \cup \left[ \frac { 1 } { 3 } , \infty \right]$
$Solve the inequality. Graph the solution set and write the solution set in interval notation. - ( 3 x - 1 ) ( x + 6 ) \leq 0 A) \left[ - \infty , \frac { 1 } { 3 } \right] B) [ - 6 , \infty ) C) \left[ - 6 , \frac { 1 } { 3 } \right] D) ( - \infty , - 6 ] \cup \left[ \frac { 1 } { 3 } , \infty \right]$

Solve the Inequality (3x−1)(x+6)≤0( 3 x - 1 ) ( x + 6 ) \leq 0(3x−1)(x+6)≤0

Multiple Choice

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Solve the Inequality $( 3 x - 1 ) ( x + 6 ) \leq 0$

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