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Solve the System {2x+y−32z=−332x−3z=0x−3y=−10\left\{ \begin{aligned}2 x + y - \frac { 3 } { 2 } z & = - 3 \\\frac { 3 } { 2 } x - 3 z & = 0 \\x - 3 y & = - 10\end{aligned} \right.

Question 143

Multiple Choice

Solve the system.
- {2x+y−32z=−332x−3z=0x−3y=−10\left\{ \begin{aligned}2 x + y - \frac { 3 } { 2 } z & = - 3 \\\frac { 3 } { 2 } x - 3 z & = 0 \\x - 3 y & = - 10\end{aligned} \right.


A) (−1,3,−2) ( - 1,3 , - 2 )
B) (−1,11,−4) ( - 1,11 , - 4 )
C) (6,3,1) ( 6,3,1 )
D) (−4,2,−2) ( - 4,2 , - 2 )

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