Solved

Decide What Values of the Variable Cannot Possibly Be Solutions xx−5−1x+9=11x2+4x−45\frac { x } { x - 5 } - \frac { 1 } { x + 9 } = \frac { 11 } { x ^ { 2 } + 4 x - 45 }

Question 2

Multiple Choice

Decide what values of the variable cannot possibly be solutions for the equation.
- xx−5−1x+9=11x2+4x−45\frac { x } { x - 5 } - \frac { 1 } { x + 9 } = \frac { 11 } { x ^ { 2 } + 4 x - 45 }


A) −5,0,9- 5,0,9
B) −9,5- 9,5
C) −9,0,5- 9,0,5
D) −5,9,−45- 5,9 , - 45

Correct Answer:

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