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Solve the Problem x225+y2324=1\frac { x ^ { 2 } } { 25 } + \frac { y ^ { 2 } } { 324 } = 1

Question 198

Multiple Choice

Solve the problem.
-A railroad tunnel is shaped like a semi-ellipse. The height of the tunnel at the center is 18 ft and the vertical clearance must be 12 ft at a point 5 ft from the center. Find an equation for the ellipse.  Solve the problem. -A railroad tunnel is shaped like a semi-ellipse. The height of the tunnel at the center is 18 ft and the vertical clearance must be 12 ft at a point 5 ft from the center. Find an equation for the ellipse.   A)   \frac { x ^ { 2 } } { 25 } + \frac { y ^ { 2 } } { 324 } = 1  B)   \frac { x ^ { 2 } } { 45 } + \frac { y ^ { 2 } } { 324 } = 1  C)   \frac { x ^ { 2 } } { 45 } + \frac { y ^ { 2 } } { 144 } = 1  D)   \frac { x ^ { 2 } } { 324 } + \frac { y ^ { 2 } } { 45 } = 1


A) x225+y2324=1\frac { x ^ { 2 } } { 25 } + \frac { y ^ { 2 } } { 324 } = 1
B) x245+y2324=1\frac { x ^ { 2 } } { 45 } + \frac { y ^ { 2 } } { 324 } = 1
C) x245+y2144=1\frac { x ^ { 2 } } { 45 } + \frac { y ^ { 2 } } { 144 } = 1
D) x2324+y245=1\frac { x ^ { 2 } } { 324 } + \frac { y ^ { 2 } } { 45 } = 1

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