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Solve the Problem Can Be Used to Estimate the Value Of

Question 138

Multiple Choice

Solve the problem.
-The series ln⁡(x) =(x−1) −(x−1) 22+(x−1) 33−…+(−1) n−1(x−1) nn\ln ( \mathrm { x } ) = ( \mathrm { x } - 1 ) - \frac { ( \mathrm { x } - 1 ) ^ { 2 } } { 2 } + \frac { ( \mathrm { x } - 1 ) ^ { 3 } } { 3 } - \ldots + ( - 1 ) ^ { \mathrm { n } - 1 } \frac { ( \mathrm { x } - 1 ) ^ { \mathrm { n } } } { \mathrm { n } } can be used to estimate the value of ln⁡(a) \ln ( a ) for any positive real number a such that 0<a≤20 < a \leq 2 . Use the first five terms of this series to estimate ln⁡(1.54) \ln ( 1.54 ) . Round to the nearest thousandth.


A) −0.495- 0.495
B) 0.4350.435
C) 1.9951.995
D) 1.3251.325

Correct Answer:

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