Give a Rule for the Piecewise-Defined Function $f ( x ) = \left\{ \begin{array} { l l } x - 3 & \text { if } x \neq 3 \\ - 2 & \text { if } x = 3 \end{array} ; \right.$

Give a rule for the piecewise-defined function. Then give the domain and range.
-

A) $f ( x ) = \left\{ \begin{array} { l l } x - 3 & \text { if } x \neq 3 \\ - 2 & \text { if } x = 3 \end{array} ; \right.$ Domain: $( - \infty , \infty )$ , Range: $( - \infty , 3 ] \cup [ 3 , \infty )$
B) $f ( x ) = \left\{ \begin{array} { l l } 2 x - 3 & \text { if } x \neq 3 \\ - 2 & \text { if } x = 3 \end{array} ; \right.$ Domain: $( - \infty , \infty )$ , Range: $( - \infty , 3 ) \cup ( 3 , \infty )$
C) $f ( x ) = \left\{ \begin{array} { l l } 2 x - 3 & \text { if } x \neq 3 \\ - 3 & \text { if } x = 3 \end{array} ; \right.$ Domain: $( - \infty , 3 ] \cup [ 3 , \infty )$ , Range: $( - \infty , \infty )$
D) $f ( x ) = \left\{ \begin{array} { l l } 2 x - 3 & \text { if } x < 3 \\ 2 x + 3 & \text { if } x \geq 3 \end{array} ; \right.$ Domain: $( - \infty , 3 ) \cup ( 3 , \infty )$ , Range: $( - \infty , \infty )$

Correct Answer:

Verified

Unlock this answer now
Get Access to more Verified Answers free of charge

Access For Free