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Solve for the Indicated Variable A=Bs1−(1+z)−t′ for tA = \frac { B s } { 1 - ( 1 + z ) ^ { - t ^ { \prime } } } \text { for } t

Question 237

Multiple Choice

Solve for the indicated variable.
- A=Bs1−(1+z) −t′ for tA = \frac { B s } { 1 - ( 1 + z ) ^ { - t ^ { \prime } } } \text { for } t


A) t=ln⁡A−ln⁡(A−Bs) ln⁡(1+z) t = \frac { \ln A - \ln ( A - B s ) } { \ln ( 1 + z ) }
B) t=ln⁡Bln⁡[(A−As) (1−z) ]t = \frac { \ln B } { \ln [ ( A - A s ) ( 1 - z ) ] }
C) t=ln⁡B(A−As) (1+z) t = \ln \frac { B } { ( A - A s ) ( 1 + z ) }
D) t=ln⁡A(A−Bs) (1+z) t = \ln \frac { A } { ( A - B s ) ( 1 + z ) }

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