Solve the Problem $\mathrm { R } = \frac { \mathrm { V } ^ { 2 } } { g ( \mathrm { f } + \tan \alpha ) }$

Solve the problem.
-A formula used by an engineer to determine the safe radius of a curve, R, when designing a particular road is: $\mathrm { R } = \frac { \mathrm { V } ^ { 2 } } { g ( \mathrm { f } + \tan \alpha ) }$ , where $\alpha$ is the superelevation of the road and $\mathrm { V }$ is the velocity (in feet per second) for which the curve is designed. If $\alpha = 2.1 ^ { \circ } , \mathrm { f } = 0.1 , \mathrm {~g} = 30$ , and $\mathrm { R } = 1195.11 \mathrm { ft }$ , find V. Round to the nearest foot per second.

A) $V = 68 \mathrm { ft }$ per sec
B) $V = 73 \mathrm { ft }$ per sec
C) $\mathrm { V } = 70 \mathrm { ft }$ per sec
D) $V = 66 \mathrm { ft }$ per sec

Correct Answer:

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