Solve the Problem $\mathrm { F }$ Of a Car Traveling Up or Down a Hill Is

Solve the problem.
-The grade resistance $\mathrm { F }$ of a car traveling up or down a hill is modeled by the equation $\mathrm { F } = \mathrm { W } \sin \theta$ , where $W$ is the weight of the car and $\theta$ is the angle of the hill's grade $( \theta > 0$ for uphill travel, $\theta < 0$ for downhill travel) . What is the grade resistance (to the nearest pound) of a $2500 - \mathrm { lb }$ car traveling downhill on a $6 ^ { \circ }$ grade $\left( \theta = - 6 ^ { \circ } \right)$ ?

A) $- 2506 \mathrm { lb }$
B) $261 \mathrm { lb }$
C) $2506 \mathrm { lb }$
D) $- 261 \mathrm { lb }$

Correct Answer:

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