Solve the Problem $F$ Of a Car Traveling Up or Down a Hill Is

Solve the problem.
-The grade resistance $F$ of a car traveling up or down a hill is modeled by the equation $F = W \sin \theta$ , where $W$ is the weight of the car and $\theta$ is the angle of the hill's grade $( \theta > 0$ for uphill travel, $\theta < 0$ for downhill travel) . What is the grade resistance (to the nearest pound) of a $1000 - \mathrm { lb }$ car traveling uphill on a $1 ^ { \circ } \operatorname { grade } \left( \theta = 1 ^ { \circ } \right)$ ?

A) $- 17 \mathrm { lb }$
B) $1001 \mathrm { lb }$
C) $- 1001 \mathrm { lb }$
D) $17 \mathrm { lb }$

Correct Answer:

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