Solve the Problem $\mathrm { I } = 80 \sin 11 \pi \mathrm { t }$

Solve the problem.
-A generator produces an alternating current according to the equation $\mathrm { I } = 80 \sin 11 \pi \mathrm { t }$ , where $t$ is time in seconds and $I$ is the current in amperes. What is the smallest time $t$ such that $I = 40$ ?

A) $\frac { 1 } { 66 } \mathrm { sec }$
B) $\frac { 1 } { 44 } \mathrm { sec }$
C) $\frac { 1 } { 22 } \mathrm { sec }$
D) $\frac { 1 } { 33 } \mathrm { sec }$

Correct Answer:

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