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Solve the Equation for Solutions in the Interval [0°, 360°) sin⁡2θ=cos⁡θ\sin 2 \theta = \cos \theta

Question 326

Multiple Choice

Solve the equation for solutions in the interval [0°, 360°) . Round to the nearest degree.
- sin⁡2θ=cos⁡θ\sin 2 \theta = \cos \theta


A) {105∘,165∘,285∘,345∘}\left\{ 105 ^ { \circ } , 165 ^ { \circ } , 285 ^ { \circ } , 345 ^ { \circ } \right\}
B) {0∘,120∘,180∘,240∘}\left\{ 0 ^ { \circ } , 120 ^ { \circ } , 180 ^ { \circ } , 240 ^ { \circ } \right\}
C) {30∘,90∘,150∘,270∘}\left\{ 30 ^ { \circ } , 90 ^ { \circ } , 150 ^ { \circ } , 270 ^ { \circ } \right\}
D) {15∘,165∘,195∘,345∘}\left\{ 15 ^ { \circ } , 165 ^ { \circ } , 195 ^ { \circ } , 345 ^ { \circ } \right\}

Correct Answer:

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