Solve the Equation for Solutions in the Interval [0, 2 $$\sin 4 x = \frac { \sqrt { 3 } } { 2 }$$

Solve the equation for solutions in the interval [0, 2 π) .
- $$\sin 4 x = \frac { \sqrt { 3 } } { 2 }$$

A) $\left\{ 0 , \frac { \pi } { 4 } , \pi \right\}$
B) $\left\{ \frac { \pi } { 12 } , \frac { \pi } { 6 } , \frac { 2 \pi } { 3 } , \frac { 7 \pi } { 12 } , \frac { 7 \pi } { 6 } , \frac { 13 \pi } { 12 } , \frac { 5 \pi } { 3 } , \frac { 19 \pi } { 12 } \right\}$
C) $\left\{ \frac { \pi } { 4 } , \frac { 5 \pi } { 4 } \right\}$
D) $\{ 0 \}$

Correct Answer:

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