Solve the Equation in the Interval [0°, 360°) $\sin ^ { 2 } \theta - \sin \theta - 12 = 0$

Solve the equation in the interval [0°, 360°) . Give solutions to the nearest tenth, if necessary.
- $\sin ^ { 2 } \theta - \sin \theta - 12 = 0$

A) $\left\{ 45 ^ { \circ } , 315 ^ { \circ } \right\}$
B) $\varnothing$
C) $\left\{ 45 ^ { \circ } , 135 ^ { \circ } \right\}$
D) $\left\{ 45 ^ { \circ } \right\}$

Correct Answer:

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