Solve the Equation in the Interval [0°, 360°) $3 \sin ^ { 2 } \theta - \sin \theta - 4 = 0$

Solve the equation in the interval [0°, 360°) . Give solutions to the nearest tenth, if necessary.
- $3 \sin ^ { 2 } \theta - \sin \theta - 4 = 0$

A) $\left\{ 180 ^ { \circ } \right\}$
B) $\left\{ 270 ^ { \circ } \right\}$
C) $\left\{ 0 ^ { \circ } \right\}$
D) $\left\{ 90 ^ { \circ } \right\}$

Correct Answer:

Verified

Unlock this answer now
Get Access to more Verified Answers free of charge

Access For Free