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Solve the Problem I(t)=7cos⁡(120πt)\mathrm { I } ( t ) = 7 \cos ( 120 \pi t )

Question 203

Multiple Choice

Solve the problem.
-Suppose that a household appliance draws a current represented by the relation I(t) =7cos⁡(120πt) \mathrm { I } ( t ) = 7 \cos ( 120 \pi t ) , where tt is time measured in seconds. The power consumed by the appliance is P=I2RP = I ^ { 2 } R , where RR is a constant. Take RR to be 16 and graph the power in [0, 0.04, 0.01] by [−200,2000,200][ - 200,2000,200 ] and use an identity to write the expression for the power in the form P=acos⁡(kπt) +d\mathrm { P } = \mathrm { a } \cos ( \mathrm { k } \pi \mathrm { t } ) + \mathrm { d } , where a\mathrm { a } , k\mathrm { k } , and d\mathrm { d } are constants.


A) P=−392cos⁡(240πt) +392\mathrm { P } = - 392 \cos ( 240 \pi \mathrm { t } ) + 392
[0,0.04,0.01][ 0,0.04,0.01 ] by [−200,2000,200][ - 200,2000,200 ]
 Solve the problem. -Suppose that a household appliance draws a current represented by the relation  \mathrm { I } ( t )  = 7 \cos ( 120 \pi t )  , where  t  is time measured in seconds. The power consumed by the appliance is  P = I ^ { 2 } R , where  R  is a constant. Take  R  to be 16 and graph the power in [0, 0.04, 0.01] by  [ - 200,2000,200 ]  and use an identity to write the expression for the power in the form  \mathrm { P } = \mathrm { a } \cos ( \mathrm { k } \pi \mathrm { t } )  + \mathrm { d } , where  \mathrm { a } ,  \mathrm { k } , and  \mathrm { d }  are constants. A)   \mathrm { P } = - 392 \cos ( 240 \pi \mathrm { t } )  + 392   [ 0,0.04,0.01 ]  by  [ - 200,2000,200 ]     B)   \mathrm { P } = 392 \cos ( 120 \pi \mathrm { t } )  + 392    [ 0,0.04,0.01 ]  by  [ - 200,2000,200 ]     C)   \mathrm { P } = 392 \cos ( 240 \pi \mathrm { t } )  + 392   [ 0,0.04,0.01 ]  by  [ - 200,2000,200 ]     D)   P = 784 \cos ( 240 \pi t )  + 784    [ 0,0.04,0.01 ]  by  [ - 200,2000,200 ]

B) P=392cos⁡(120πt) +392\mathrm { P } = 392 \cos ( 120 \pi \mathrm { t } ) + 392
[0,0.04,0.01][ 0,0.04,0.01 ] by [−200,2000,200][ - 200,2000,200 ]
 Solve the problem. -Suppose that a household appliance draws a current represented by the relation  \mathrm { I } ( t )  = 7 \cos ( 120 \pi t )  , where  t  is time measured in seconds. The power consumed by the appliance is  P = I ^ { 2 } R , where  R  is a constant. Take  R  to be 16 and graph the power in [0, 0.04, 0.01] by  [ - 200,2000,200 ]  and use an identity to write the expression for the power in the form  \mathrm { P } = \mathrm { a } \cos ( \mathrm { k } \pi \mathrm { t } )  + \mathrm { d } , where  \mathrm { a } ,  \mathrm { k } , and  \mathrm { d }  are constants. A)   \mathrm { P } = - 392 \cos ( 240 \pi \mathrm { t } )  + 392   [ 0,0.04,0.01 ]  by  [ - 200,2000,200 ]     B)   \mathrm { P } = 392 \cos ( 120 \pi \mathrm { t } )  + 392    [ 0,0.04,0.01 ]  by  [ - 200,2000,200 ]     C)   \mathrm { P } = 392 \cos ( 240 \pi \mathrm { t } )  + 392   [ 0,0.04,0.01 ]  by  [ - 200,2000,200 ]     D)   P = 784 \cos ( 240 \pi t )  + 784    [ 0,0.04,0.01 ]  by  [ - 200,2000,200 ]

C) P=392cos⁡(240πt) +392\mathrm { P } = 392 \cos ( 240 \pi \mathrm { t } ) + 392
[0,0.04,0.01][ 0,0.04,0.01 ] by [−200,2000,200][ - 200,2000,200 ]
 Solve the problem. -Suppose that a household appliance draws a current represented by the relation  \mathrm { I } ( t )  = 7 \cos ( 120 \pi t )  , where  t  is time measured in seconds. The power consumed by the appliance is  P = I ^ { 2 } R , where  R  is a constant. Take  R  to be 16 and graph the power in [0, 0.04, 0.01] by  [ - 200,2000,200 ]  and use an identity to write the expression for the power in the form  \mathrm { P } = \mathrm { a } \cos ( \mathrm { k } \pi \mathrm { t } )  + \mathrm { d } , where  \mathrm { a } ,  \mathrm { k } , and  \mathrm { d }  are constants. A)   \mathrm { P } = - 392 \cos ( 240 \pi \mathrm { t } )  + 392   [ 0,0.04,0.01 ]  by  [ - 200,2000,200 ]     B)   \mathrm { P } = 392 \cos ( 120 \pi \mathrm { t } )  + 392    [ 0,0.04,0.01 ]  by  [ - 200,2000,200 ]     C)   \mathrm { P } = 392 \cos ( 240 \pi \mathrm { t } )  + 392   [ 0,0.04,0.01 ]  by  [ - 200,2000,200 ]     D)   P = 784 \cos ( 240 \pi t )  + 784    [ 0,0.04,0.01 ]  by  [ - 200,2000,200 ]

D) P=784cos⁡(240πt) +784P = 784 \cos ( 240 \pi t ) + 784
[0,0.04,0.01][ 0,0.04,0.01 ] by [−200,2000,200][ - 200,2000,200 ]
 Solve the problem. -Suppose that a household appliance draws a current represented by the relation  \mathrm { I } ( t )  = 7 \cos ( 120 \pi t )  , where  t  is time measured in seconds. The power consumed by the appliance is  P = I ^ { 2 } R , where  R  is a constant. Take  R  to be 16 and graph the power in [0, 0.04, 0.01] by  [ - 200,2000,200 ]  and use an identity to write the expression for the power in the form  \mathrm { P } = \mathrm { a } \cos ( \mathrm { k } \pi \mathrm { t } )  + \mathrm { d } , where  \mathrm { a } ,  \mathrm { k } , and  \mathrm { d }  are constants. A)   \mathrm { P } = - 392 \cos ( 240 \pi \mathrm { t } )  + 392   [ 0,0.04,0.01 ]  by  [ - 200,2000,200 ]     B)   \mathrm { P } = 392 \cos ( 120 \pi \mathrm { t } )  + 392    [ 0,0.04,0.01 ]  by  [ - 200,2000,200 ]     C)   \mathrm { P } = 392 \cos ( 240 \pi \mathrm { t } )  + 392   [ 0,0.04,0.01 ]  by  [ - 200,2000,200 ]     D)   P = 784 \cos ( 240 \pi t )  + 784    [ 0,0.04,0.01 ]  by  [ - 200,2000,200 ]

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