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Use Cramerʹs Rule to Solve the System of Equations 2x+4y+8z=40x+2y+4z=−10x+y+z=−4\begin{array} { l } 2 x + 4 y + 8 z = 40 \\x + 2 y + 4 z = - 10 \\x + y + z = - 4\end{array}

Question 131

Multiple Choice

Use Cramerʹs rule to solve the system of equations. If D = 0, use another method to determine the solution set.
- 2x+4y+8z=40x+2y+4z=−10x+y+z=−4\begin{array} { l } 2 x + 4 y + 8 z = 40 \\x + 2 y + 4 z = - 10 \\x + y + z = - 4\end{array}


A) Cramer's rule does not apply since D=0D = 0 ; ∅\varnothing
B) Cramer's rule does not apply since D=0;{(2z−1,z+2,z) }D = 0 ; \{ ( 2 z - 1 , z + 2 , z ) \}
C) {(−5,3,−4) }\{ ( - 5,3 , - 4 ) \}
D) {(−4,−5,3) }\{ ( - 4 , - 5,3 ) \}

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