Find the Inverse Function of F $$f ( x ) = \frac { 3 x - 2 } { x + 5 }$$

Find the inverse function of f. State the domain and range of f.
- $$f ( x ) = \frac { 3 x - 2 } { x + 5 }$$

A) $\mathrm { f } ^ { - 1 } ( \mathrm { x } ) = \frac { \mathrm { x } + 5 } { 3 \mathrm { x } - 2 }$ ; domain of $\mathrm { f } : \{ \mathrm { x } \mid \mathrm { x } \neq - 5 \}$ ; range of $\mathrm { f } : \left\{ \mathrm { y } \mid \mathrm { y } \neq \frac { 2 } { 3 } \right\}$

B) $\mathrm { f } ^ { - 1 } ( \mathrm { x } ) = \frac { 5 \mathrm { x } + 2 } { 3 + \mathrm { x } }$ ; domain of $\mathrm { f } : \{ \mathrm { x } \mid \mathrm { x } \neq5 \}$ ; range of $\mathrm { f } : \{ \mathrm { y } \mid \mathrm { y } \neq 3 \}$

C) $f ^ { - 1 } ( x ) = \frac { 3 x + 2 } { x - 5 }$ ; domain of $f : \{ x \mid x \neq - 5 \}$ ; range of $f : \{ y \mid y \neq 5 \}$

D) $f ^ { - 1 } ( x ) = \frac { 5 x + 2 } { 3 - x }$ ; domain of $f : \{ x \mid x \neq - 5 \}$ ; range of $f : \{ y \mid y \neq 3 \}$

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