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Complete the Identity csc⁡(2θ)−sec⁡(2θ)(tan⁡θ−1)=\csc ( 2 \theta ) - \sec ( 2 \theta ) ( \tan \theta - 1 ) =

Question 158

Multiple Choice

Complete the identity.
- csc⁡(2θ) −sec⁡(2θ) (tan⁡θ−1) =\csc ( 2 \theta ) - \sec ( 2 \theta ) ( \tan \theta - 1 ) = ?


A) sin⁡θ+cos⁡θsin⁡(2θ) (sin⁡θ−cos⁡θ) \frac { \sin \theta + \cos \theta } { \sin ( 2 \theta ) ( \sin \theta - \cos \theta ) }

B) csc⁡θ−sec⁡θsin⁡(2θ) (sin⁡θ+cos⁡θ) \frac { \csc \theta - \sec \theta } { \sin ( 2 \theta ) ( \sin \theta + \cos \theta ) }

C) csc⁡θ+sec⁡θsin⁡(2θ) (sin⁡θ−cos⁡θ) \frac { \csc \theta + \sec \theta } { \sin ( 2 \theta ) ( \sin \theta - \cos \theta ) }

D) cos⁡θ−sin⁡θsin⁡(2θ) (sin⁡θ+cos⁡θ) \frac { \cos \theta - \sin \theta } { \sin ( 2 \theta ) ( \sin \theta + \cos \theta ) }

Correct Answer:

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