Solve the Equation on the Interval $$0 \leq \theta < 2 \pi \text {. }$$

Solve the equation on the interval $$0 \leq \theta < 2 \pi \text {. }$$
- $\sqrt { 3 } \sin \theta - \cos \theta = - 1$

A) $\frac { 3 \pi } { 2 } , \frac { \pi } { 6 }$

B) $0 , \frac { 4 \pi } { 3 }$

C) $\frac { \pi } { 2 } , \frac { 7 \pi } { 6 }$

D) $0 , \frac { 2 \pi } { 3 }$

Correct Answer:

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